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 Bar Bending schedule For Footing :-

FOOTING

Details Obtained from Structural Drawing

Following details are obtained from the drawings and specifications:

1. Length of Footing = X
2. The breadth of Footing = Y
3. The height of the footing (Thickness) = h
4. The diameter of the Main reinforcement bars = d_m
5. The diameter of Distribution Reinforcement Bars = d_d
6. The spacing of reinforcement bars = s
7. Cover for reinforcement = c

Formulas for Calculation

From the figure-1, the following parameters are determined:

1. Number of Main Reinforcement Bars ( X-Bars)
2. Number of Distribution Reinforcement Bars ( Y-Bars)
3. Cutting Length of Main Reinforcement Bars (Cm)
4. Cutting Length of Distribution Reinforcement Bars (Cd)
5. Steel Quantity Required

Footing:-

 

   1. Cutting Length of Main Reinforcement (X-Bars) Cm1     = [Length of Footing – 2(cover)]           +2[ Thickness of footing -2(cover)] - 2[Bend] From the figure,

Cm1     = [X-2C] +2[h-2C]-2[2d_m] 

2. Cutting Length of Distribution Reinforcement (Y-Bars) Cd= [Breadth of Footing – 2(cover)] +2[ Thickness of footing -2(cover)] - 2[Bend] From the figure,

Cd1      = [Y-2C] +2[h-2C]-2[2d_m]

 Bar Bending Schedule For Isolated Footing

Example :-

1. Bar Type :-Main Reinforcement (X-Bars) , Dia: of Bar (mm):-    12, 

Shape of Bar:-U,  No: of Bar:-11, Length of Bar(m) :- 2.252,

Total Length of Bar(m) :- 24.772, Weight of 1m length Bar (Kg) :-0.889,  Total Weight of Bar Kg :-22.02,

1. Bar Type :-Main Reinforcement (Y-Bars) , Dia: of Bar (mm):-    12, 

Shape of Bar:-U,  No: of Bar:-14 ,  Length of Bar(m) :- 1.852 ,

Total Length of Bar(m) :- 23.05,  Weight of 1m length Bar (Kg) :-0.889,  Total Weight of Bar Kg :- 23.05,

TOTAL = 45.07

COLUMN :-

1. COLUMN BEND LENGTH 16D

2. LAPPING LENGTH OF COLUMN 41d

3. 16 MM 2FT

4. 12 NN 1.5FT